A nucleus of an element {}_{84}X^{202} emits | vedclass

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Question

(C) The initial nucleus is ${}_{84}X^{202}$.$1$. After $\alpha$-decay: The atomic number decreases by $2$ and the mass number decreases by $4$.${}_{84

Vedclass · Accepted Answer

$83$

Vedclass · Answer

(C) The initial nucleus is ${}_{84}X^{202}$.$1$. After $\alpha$-decay: The atomic number decreases by $2$ and the mass number decreases by $4$.${}_{84}X^{202} \rightarrow {}_{82}Y^{198} + {}_{2}He^{4}$.$2$. After $\beta$-decay: The atomic number increases by $1$ and the mass number remains unchanged.${}_{82}Y^{198} \rightarrow {}_{83}Z^{198} + {}_{-1}e^{0}$.$3$. After $\gamma$-emission: The atomic number and mass number remain unchanged.${}_{83}Z^{198} \rightarrow {}_{83}Z^{198} + \gamma$.The final nucleus formed is ${}_{83}Z^{198}$,which has an atomic number of $83$.

$A$ nucleus of an element ${}_{84}X^{202}$ emits an $\alpha$-particle first,a $\beta$-particle next,and then a gamma photon. The final nucleus formed has an atomic number:

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